20c^2-41cw+20w^2=0

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Solution for 20c^2-41cw+20w^2=0 equation: 


Simplifying
20c2 + -41cw + 20w2 = 0

Reorder the terms:
-41cw + 20c2 + 20w2 = 0

Solving
-41cw + 20c2 + 20w2 = 0

Solving for variable 'c'.

Factor a trinomial.
(4c + -5w)(5c + -4w) = 0


Subproblem 1
Set the factor '(4c + -5w)' equal to zero and attempt to solve:

Simplifying
4c + -5w = 0

Solving
4c + -5w = 0

Move all terms containing c to the left, all other terms to the right.

Add '5w' to each side of the equation.
4c + -5w + 5w = 0 + 5w

Combine like terms: -5w + 5w = 0
4c + 0 = 0 + 5w
4c = 0 + 5w
Remove the zero:
4c = 5w

Divide each side by '4'.
c = 1.25w

Simplifying
c = 1.25w

Subproblem 2
Set the factor '(5c + -4w)' equal to zero and attempt to solve:

Simplifying
5c + -4w = 0

Solving
5c + -4w = 0

Move all terms containing c to the left, all other terms to the right.

Add '4w' to each side of the equation.
5c + -4w + 4w = 0 + 4w

Combine like terms: -4w + 4w = 0
5c + 0 = 0 + 4w
5c = 0 + 4w
Remove the zero:
5c = 4w

Divide each side by '5'.
c = 0.8w

Simplifying
c = 0.8w
Solution
c = {1.25w, 0.8w}

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